A useful solution to the wave equation for an ideal string is:
y(x,t) = Asin(2π/λ(x+/-vt))
This is a solution to the one-dimensional wave equation (via direct substitution):
∂ ² / ∂x² = (ρ/T)(∂²y/∂t²)
giving us:
1 = (ρ/T)v²
giving the wave velocity of a stretched string:
v = √(T/ρ)
where T = tension in the string
and the mass her unit length:
ρ = m/L
No comments:
Post a Comment